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Two IHPI teams compete in NEJM SPRINT Data Challenge
Two teams that include IHPI members and U-M students are competing in the SPRINT Data Analysis Challenge, being run by the New England Journal of Medicine as a way of stimulating new uses of clinical trial data available in the public domain.
Voting ends Feb. 28 for the crowd-voting portion of the challenge, which lets anyone review the submissions from teams around the world and vote for their favorite.
The IHPI-member teams, and their competitors, all made it to the crowd-voting segment of the competition after making it through a panel of judges that evaluated the initial submissions and chose a subset for the Challenge Round. Each team analyzed the dataset underlying the NEJM article about the SPRINT trial, A Randomized Trial of Intensive versus Standard Blood-Pressure Control (N Engl J Med 373: 2103-2116) — and identified a novel scientific or clinical finding that advances medical science.
See the two submissions with IHPI ties here -- and sign up for a free account to be able to vote:
Development and Validation of a Clinical Decision Score to Maximize Benefit and Minimize Harm from Intensive Blood Pressure Treatment
IHPI members Jeremy B Sussman, M.D., M.Sc., Brian Denton, Ph.D, and Rodney Hayward, M.D. teamed up with Lauren N. Steimle, a Ph.D. Candidate in U-M's Industrial and Operations Engineering program, and Joseph Rigdon, a biostatistician at Stanford University. They developed and validated a clinical decision score to identify patients likely to experience benefits and unlikely to experience harms when undergoing intensive treatment.
The incremental effects of antihypertensive drugs: an instrumental variable analysis of the SPRINT trial
Crowdvoting counts for 10 percent of the total criteria used to determine the winners of the Challenge Round.
![Jeremy Sussman](/sites/default/files/styles/expert/public/images/members/jeremy%2520sussman.jpg?itok=27ZufYOd)
![Andrew Ryan](/sites/default/files/styles/expert/public/2019-02/andrew%20ryan%202018.jpg?itok=kub3xgUR)